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Waves and interference questions

Calculate phase, fringe spacing and string harmonics; add wave displacements.

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Separation and phase

Two points on the same progressive wave are 0.15 m apart along its direction of travel. Wavelength is 1.2 m. Calculate their phase separation as a positive angle from 0° to 360°, using 360° for one wavelength. Keep angles above 180° in this convention. Give your answer to 3 significant figures.

One cycle = λ
Schematic snapshot of a progressive transverse wave. One complete spatial cycle is one wavelength.
Larger diagram
One cycle = λ

Treat the given values as exact unless an uncertainty is stated.

Use decimals or e notation, e.g. 4.2e-3. Enter the unit separately.

Hint

The phase difference is the separation as a fraction of a wavelength, multiplied by 360°.

Worked solution
  1. Phase difference = (0.15/1.2) × 360°.
  2. Answer: 45.0 ° (3 significant figures).
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Question type: Separation and phase
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A cycle in space and time

Wavelength is the distance for one complete spatial cycle; period is the time for one cycle. Use v = fλ and f = 1/T. For points on a progressive wave, phase-difference magnitude in degrees is 360° × separation/λ. These phase tasks use separations less than one wavelength and request a positive angle from 0° to 360°, including angles above 180°. They do not ask for the smaller equivalent angle or a signed phase lead.

Superposition and interference

Add instantaneous displacements with their signs. Coherent sources have a constant phase difference. For sources in phase, integer-wavelength path differences give constructive interference; half-integer differences give destructive interference. Complete cancellation also requires equal amplitudes at the observation point.

Fringes and stationary waves

Young’s double-slit formula w = λD/s gives adjacent bright-fringe spacing under the small-angle approximation. Keep wavelengths and distances in compatible units. Adjacent nodes of a stationary wave are λ/2 apart. A string fixed at both ends contains n half-wavelengths at harmonic n, so f = nv/(2L). Open and closed pipes, diffraction patterns and refraction are outside this resource’s scope.

A-level relevance

AQA 7408: 3.3.1.1–3, 3.3.2.2 (selected); OCR A H556: 4.4.1; 4.4.3–4 (selected). Tasks cover the selected skills listed above.

AQA specification · OCR A specification