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Simple harmonic motion questions

Calculate periods, signed acceleration, speed and energy; use the small-angle pendulum model.

Practise

Oscillator energy

A 0.2 kg object undergoes undamped SHM with period 1.2 s and amplitude 4 cm. Calculate its total oscillation energy, taking potential energy as zero at equilibrium. Give your answer to 3 significant figures.

Treat the given values as exact unless an uncertainty is stated.

Use decimals or e notation, e.g. 4.2e-3. Enter the unit separately.

Hint

At equilibrium all oscillation energy is kinetic: E = ½m(ωA)².

Worked solution
  1. E = ½ × 0.2 × (2π/1.2)² × 0.04² J.
  2. This is energy relative to equilibrium, not the absolute gravitational or spring energy.
  3. Answer: 4.39 × 10-3 J (3 significant figures).
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Question type: Mixed practice
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Displacement, velocity and acceleration

SHM is motion with acceleration proportional to displacement and directed towards equilibrium: a = −ω²x. Angular frequency ω = 2π/T = 2πf. A negative displacement gives a positive acceleration; it does not determine which way the object is moving.

Speed and energy

Speed = ω√(A² − x²), with A and x in metres. Maximum speed ωA occurs at equilibrium; speed is zero at the turning points. For an undamped oscillator, total oscillation energy relative to equilibrium is ½mω²A².

Spring and pendulum periods

A mass on a Hooke-law spring has T = 2π√(m/k), measured about its loaded equilibrium. A simple pendulum has T = 2π√(L/g) at small angles, where L runs from pivot to the bob’s centre. Use a light, inextensible string and a point-mass bob.

What this practice covers

Selected period, frequency, acceleration, speed, energy and model calculations. Damping, resonance, phase calculations and full practical methods are outside this set. Numerical answers use 3 significant figures; use the constants supplied in each question.

A-level relevance

AQA 7408: 3.6.1.2–3 (selected); OCR A H556: 5.3.1–2 (selected). Tasks cover the selected skills listed above.

AQA specification · OCR A specification