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Free fall practical questions

Process repeated timings, find g from squared-time graphs and evaluate timing errors.

Practise

Height–time² gradient

Calculate the supplied h–t² line gradient from the first and last mean-time readings. Give 3 significant figures.

Practical setup and assumptions

A ball is released from rest. Electronic timing measures release to impact; h is the vertical displacement of the same reference point on the ball. Ignore drag and use constant downward acceleration.

These are generated practice readings. Their mean times follow h = ½gt² exactly. Use any stated uncertainties; do not estimate uncertainty from the spread of these readings.

Readings for this dataset
Repeat readings for five heights
h / mt₁ / st₂ / st₃ / s
0.155520.1790.180.181
0.232320.2190.220.221
0.324480.2590.260.261
0.4320.2990.30.301
0.554880.3390.340.341

The linked tasks use the same readings. These are generated practice data: treat them as exact unless an uncertainty is stated. Use the stated uncertainty rather than estimating it from scatter.

Height against squared mean fall timePractice readings with a given straight line; use the line shown for calculations. Horizontal axis: Mean time² / s², 0 to 0.2. Vertical axis: Height / m, 0 to 1. Exact values are also listed below the graph.00.020.040.060.080.10.120.140.160.180.200.10.20.30.40.50.60.70.80.91Mean time² / s²Height / m12345
Read the axes and units. The values are also available in the table below.
Larger graph
Height against squared mean fall timePractice readings with a given straight line; use the line shown for calculations. Horizontal axis: Mean time² / s², 0 to 0.2. Vertical axis: Height / m, 0 to 1. Exact values are also listed below the graph.00.020.040.060.080.10.120.140.160.180.200.10.20.30.40.50.60.70.80.91Mean time² / s²Height / m12345
Graph values
Coordinates
PointMean time² / s²Height / m
10.03240.15552
20.04840.23232
30.06760.32448
40.090.432
50.11560.55488

Use decimals or e notation, e.g. 4.2e-3. Enter the unit separately.

Hint

Gradient = Δh/Δ(t²).

Worked solution
  1. Gradient = (0.55488 − 0.15552)/(0.1156 − 0.0324) m s⁻².
  2. Answer: 4.80 m s⁻² (3 significant figures).
Next task in this dataset
Work through this dataset
  1. Mean repeated time
  2. Square the mean time
  3. Choose linear axes
  4. Height–time² gradient (current)
  5. Find g
  6. Reverse the axes
  7. Predict a fall time
  8. Speed before impact
  9. Timing percentage uncertainty
  10. Uncertainty in g
  11. A timing offset
  12. Release from rest

These tasks keep the same readings. Another question starts a new dataset. Your answers are checked separately.

Another question
Question type: Height–time² gradient
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Mean time and graph orientation

For a ball released from rest with negligible drag, h = ½gt². Calculate the mean time at each height, then square that mean. A graph of h vertically against t² has gradient g/2. Reversing the axes gives gradient 2/g.

Timing and release errors

The timer must measure the fall from release to impact. Measure displacement between matching reference points. A downward push adds an initial-velocity term ut. A positive timing offset makes a single-height 2h/t² estimate too low; repeats do not remove that offset.

Uncertainty

For the stated first-order maximum method, percentage uncertainty in g = 2h/t² is the height percentage plus twice the time percentage. Use the separately quoted uncertainties; the synthetic repeat spread is not a universal instrument rule. These tasks cover selected data skills, not a full laboratory procedure.

A-level relevance

AQA 7408: 3.4.1.3; required practical 3 (selected); OCR A H556: 3.1.2(a–b) (selected). Tasks cover the selected skills listed above.

AQA mechanics and materials specification · OCR A specification · AQA practical handbook · OCR practical skills handbook