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Work, energy and momentum questions

Calculate work and power, conserve signed momentum and compare collision energies.

Practise

Work at an angle

A constant 32 N force pulls an object through a horizontal displacement of 7 m. The force is 30° above the displacement direction. Find the work done by this force. Give your answer to 3 significant figures.

Displacement 7 mForce 32 N30°
Force 32 N at 30° above a horizontal displacement of 7 m. The angle is between force and displacement; arrow lengths are schematic.
Larger diagram
Displacement 7 mForce 32 N30°

Treat the given values as exact unless an uncertainty is stated.

Use decimals or e notation, e.g. 4.2e-3. Enter the unit separately.

Hint

Only the force component parallel to displacement does work: W = Fs cos θ.

Worked solution
  1. W = 32 × 7 × cos(30°) J.
  2. Answer: 194 J (3 significant figures).
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Question type: Work at an angle
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Choose the system before conserving anything

Momentum is conserved when external impulse on the chosen system is negligible. Keep velocity signs in one-dimensional collisions. Objects that stick share a final velocity, but their total kinetic energy usually decreases. Total energy is still conserved; some becomes internal energy.

Work and power

A constant force does work Fs cos θ, using the angle between force and displacement. Useful lifting power is mgh/t. At steady speed against a resistive force F, the required mechanical power is Fv. Efficiency compares useful output with total input.

Impulse has a direction

Impulse = m(v − u). A rebound changes the velocity sign. Average resultant force is impulse divided by contact time; it is not necessarily the peak force. This resource covers selected constant-force energy calculations, one-dimensional sticking collisions and impulse, not a complete mechanics course.

A-level relevance

AQA 7408: 3.4.1.6–8 (selected); OCR A H556: 3.3.1–3; 3.5.1–2 (selected). Tasks cover the selected skills listed above.

AQA mechanics and materials specification · OCR A specification