Current–voltage characteristics practical
Connect an ammeter and voltmeter correctly, interpret resistor and lamp data, and evaluate heating.
Practise the calculations · Print a classroom set
Apparatus and measurements
Use a low-voltage supply, switch, variable resistor and ammeter in series with the component. Connect a voltmeter in parallel across the component. A diode needs a suitable series current-limiting resistor.
Larger apparatus diagram
Method and controls
- Begin with a small current. Change the variable resistance or supply setting and record the component current and potential difference together.
- For negative readings, switch off and reverse the supply polarity, then repeat. Keep the same instrument sign convention. Never reconnect a circuit while the supply is on.
- Plot current vertically against potential difference horizontally. A constant-temperature resistor gives a straight line through the origin; a filament lamp’s changing temperature produces a curve.
Results to analyse
Original synthetic data for practice.
| Potential difference / V | Resistor current / A | Lamp current / A |
|---|---|---|
| 0 | 0 | 0 |
| 1 | 0.10 | 0.15 |
| 2 | 0.20 | 0.24 |
| 3 | 0.30 | 0.30 |
Questions
- Find the resistor resistance at 2 V. What is the gradient of its current–voltage graph?
- Find the lamp resistance at 1 V and 3 V. Explain its change.
- Why is an ammeter connected in parallel across the supply a poor connection?
Show worked answers
- R = V/I = 2/0.20 = 10 Ω. The I–V gradient is 0.10 A V⁻¹ = 1/R, not R.
- At 1 V, R = 1/0.15 = 6.67 Ω; at 3 V, R = 3/0.30 = 10.0 Ω. The hotter filament has greater resistance.
- An ammeter has low resistance. Across the supply it can draw a large current and damage the meter or circuit. It belongs in series.
Evaluation
Switch off between readings when temperature should stay constant. A filament lamp deliberately changes temperature during its characteristic, so do not describe all component heating as an unwanted effect.
Use suitable instrument ranges and a current-limited school supply. A diode’s reverse current is very small over its normal range; avoid destructive reverse voltages.
Specification links
AQA 8463: Required practical 4; 4.2.1.4. OCR Gateway J249: P3.2; PAG P6 (selected). Selected skills only; no practical-completion assessment.
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