Testing a pendulum with a length offset
14 marks · A-level · original practice case
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The situation
A student measures the period of a small-amplitude pendulum at several lengths. Length L is measured from the support to the top of a spherical bob of radius 0.020 m. The string is light and inextensible. The simulated times are for 20 complete oscillations. Use g = 9.81 m s⁻² when predicting an intercept. For this investigation use the small-amplitude model T = 2π√(l/g), where l is the distance from the pivot to the bob’s centre; this relation is provided for OCR A students.
| L / m | Time for 20 oscillations / s |
|---|---|
| 0.300 | 22.70 |
| 0.400 | 25.99 |
| 0.500 | 28.91 |
| 0.600 | 31.61 |
| 0.700 | 34.03 |
Learn support
Decide which length belongs in the pendulum model. A linearised plot can separate a slope from a length offset.
Part (a)
Construct a graph that can be used to determine g from these data. Calculate any additional values you need. Draw the graph on paper. [3 marks]
Part (b)
Determine g from the gradient of your graph. [3 marks]
Give the numerical answer to 3 significant figures. Graph readings between 9.5 and 10.2 m s⁻² are accepted.
Part (c)
Calculate the intercept predicted by the stated length convention. [2 marks]
Give the numerical answer to 3 significant figures.
Part (d)
Design an improved experiment to determine g and test whether the apparent intercept is caused by the length convention. Explain how you would analyse the measurements and assess the main limitations. [6 marks]
Marking rubric and worked answers
Indicative practice marks. Method marks assess valid working; accuracy marks require the associated valid method. Independent points stand on their own. Tick only points supported by your response. Do not award the same explanation twice. These ticks record your judgement, not an examiner’s result.
Part (a) marking points
Credit equivalent correct explanations. Award each distinct point once; a contradiction invalidates the affected point.
Acceptable alternatives: Plot L against T² with the axes and later gradient calculation changed consistently.
Part (b) marking points
Final answer: 9.83 m s⁻². Numerical checks assess the final value only; they do not check working or the number of digits typed.
Allow a defensible best-fit gradient within the stated range. After a plotting/arithmetic error, credit the correct relationship to the student’s own gradient; no full accuracy credit outside the range. Do not credit g = 4π² × gradient for these axes.
Acceptable alternatives: For L vertically against T², g = 4π² × gradient.
Part (c) marking points
Final answer: 0.0805 s². Numerical checks assess the final value only; they do not check working or the number of digits typed.
No earlier numerical result is required. Credit a valid alternative method. Accuracy credit requires a physically valid method.
Part (d) marking points
Assess the response as a whole. Indicative content:
- Measure pivot to bob centre; repeat with both length conventions and predict the intercept difference using the bob radius.
- Use a small measured angular amplitude and keep it similar; release without pushing.
- Time many complete cycles with a fixed fiducial point, repeat timings, and calculate a mean period with a repeat-based uncertainty.
- Use a wide range of measured lengths; plot T² against effective length and determine g from a best-fit gradient.
- Compare the fitted intercept with its uncertainty; use extreme acceptable slopes or regression uncertainty to assess uncertainty in g.
- Check pivot position, bob radius, timing/counting errors and amplitude dependence; repeating timings cannot remove a shared length bias.
Level 1 (1–2): Some relevant apparatus or timing steps, with little connection to analysis or the intercept.
Level 2 (3–4): A workable measurement and graph method, with an explained improvement or length-offset test. Analysis or uncertainty is incomplete.
Level 3 (5–6): A coherent, reproducible method links centre-of-bob length, timing and graph analysis to g and the intercept test, and evaluates the main uncertainties with justified improvements.
Judge the response as a whole against the levels. The indicative content is not a checklist of six marks. Choose the lower mark in a band for a borderline response and the upper mark for a response that consistently meets the descriptor. No relevant correct physics: 0 marks.
Self-assessed marks: 0 / 14
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Related skills
Scope and reference sources
AQA 3.6.1.3 and practical/mathematical skills; OCR A 5.3.1 and Modules 1/2. These are shared original exercises; wording, indicative marks and difficulty have not been endorsed by either board.
AQA specification · OCR A specification
Case reference: pendulum-length-offset · version 1.1.0 · seed 0. Choose another case